Search a number
-
+
1200642497 is a prime number
BaseRepresentation
bin100011110010000…
…0101100111000001
310002200012221212122
41013210011213001
54424331024442
6315045534025
741516202305
oct10744054701
93080187778
101200642497
1156680552a
12296114315
1316198aa62
14b5659d05
1570615dd2
hex479059c1

1200642497 has 2 divisors, whose sum is σ = 1200642498. Its totient is φ = 1200642496.

The previous prime is 1200642463. The next prime is 1200642511. The reversal of 1200642497 is 7942460021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1199306161 + 1336336 = 34631^2 + 1156^2 .

It is an emirp because it is prime and its reverse (7942460021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1200642497 - 28 = 1200642241 is a prime.

It is not a weakly prime, because it can be changed into another prime (1200642407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600321248 + 600321249.

It is an arithmetic number, because the mean of its divisors is an integer number (600321249).

Almost surely, 21200642497 is an apocalyptic number.

It is an amenable number.

1200642497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200642497 is an equidigital number, since it uses as much as digits as its factorization.

1200642497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 35.

The square root of 1200642497 is about 34650.2885557970. The cubic root of 1200642497 is about 1062.8481894956.

The spelling of 1200642497 in words is "one billion, two hundred million, six hundred forty-two thousand, four hundred ninety-seven".