Base | Representation |
---|---|
bin | 10110010111100111… |
… | …01010000010010001 |
3 | 1010222221112011021122 |
4 | 23023303222002101 |
5 | 144043332012321 |
6 | 5303355532025 |
7 | 603412643321 |
oct | 131363520221 |
9 | 33887464248 |
10 | 12009250961 |
11 | 51029aaaa4 |
12 | 23b1a5a015 |
13 | 1195053476 |
14 | 81cd49281 |
15 | 4a449b8ab |
hex | 2cbcea091 |
12009250961 has 2 divisors, whose sum is σ = 12009250962. Its totient is φ = 12009250960.
The previous prime is 12009250943. The next prime is 12009250963. The reversal of 12009250961 is 16905290021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11070196225 + 939054736 = 105215^2 + 30644^2 .
It is an emirp because it is prime and its reverse (16905290021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12009250961 - 214 = 12009234577 is a prime.
Together with 12009250963, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12009250963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6004625480 + 6004625481.
It is an arithmetic number, because the mean of its divisors is an integer number (6004625481).
Almost surely, 212009250961 is an apocalyptic number.
It is an amenable number.
12009250961 is a deficient number, since it is larger than the sum of its proper divisors (1).
12009250961 is an equidigital number, since it uses as much as digits as its factorization.
12009250961 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 35.
The spelling of 12009250961 in words is "twelve billion, nine million, two hundred fifty thousand, nine hundred sixty-one".
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