12010023433 has 2 divisors, whose sum is σ = 12010023434. Its totient is φ = 12010023432.

The previous prime is 12010023419. The next prime is 12010023451. The reversal of 12010023433 is 33432001021.

12010023433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11987622144 + 22401289 = 109488^2 + 4733^2 .

It is an emirp because it is prime and its reverse (33432001021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12010023433 is a prime.

It is a super-2 number, since 2×12010023433² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12010023433.

It is not a weakly prime, because it can be changed into another prime (12010023833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005011716 + 6005011717.

It is an arithmetic number, because the mean of its divisors is an integer number (6005011717).

Almost surely, 2^12010023433 is an apocalyptic number.

It is an amenable number.

12010023433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12010023433 is an equidigital number, since it uses as much as digits as its factorization.

12010023433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 12010023433 its reverse (33432001021), we get a palindrome (45442024454).

The spelling of 12010023433 in words is "twelve billion, ten million, twenty-three thousand, four hundred thirty-three".