12010040113 has 4 divisors (see below), whose sum is σ = 12010260340. Its totient is φ = 12009819888.

The previous prime is 12010040101. The next prime is 12010040149. The reversal of 12010040113 is 31104001021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2872209649 + 9137830464 = 53593^2 + 95592^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12010040113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12010040093 and 12010040102.

It is not an unprimeable number, because it can be changed into a prime (12010040183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38983 + ... + 159811.

It is an arithmetic number, because the mean of its divisors is an integer number (3002565085).

Almost surely, 2^12010040113 is an apocalyptic number.

It is an amenable number.

12010040113 is a deficient number, since it is larger than the sum of its proper divisors (220227).

12010040113 is an equidigital number, since it uses as much as digits as its factorization.

12010040113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 220226.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 12010040113 its reverse (31104001021), we get a palindrome (43114041134).

The spelling of 12010040113 in words is "twelve billion, ten million, forty thousand, one hundred thirteen".