120101014121 has 4 divisors (see below), whose sum is σ = 131019288144. Its totient is φ = 109182740100.

The previous prime is 120101014087. The next prime is 120101014139. The reversal of 120101014121 is 121410101021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120101014121 - 2³⁰ = 119027272297 is a prime.

It is a super-3 number, since 3×120101014121³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120101014096 and 120101014105.

It is not an unprimeable number, because it can be changed into a prime (120101014141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5459136995 + ... + 5459137016.

It is an arithmetic number, because the mean of its divisors is an integer number (32754822036).

Almost surely, 2^120101014121 is an apocalyptic number.

120101014121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

120101014121 is a deficient number, since it is larger than the sum of its proper divisors (10918274023).

120101014121 is a wasteful number, since it uses less digits than its factorization.

120101014121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10918274022.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 120101014121 its reverse (121410101021), we get a palindrome (241511115142).

The spelling of 120101014121 in words is "one hundred twenty billion, one hundred one million, fourteen thousand, one hundred twenty-one".