12010130113 has 2 divisors, whose sum is σ = 12010130114. Its totient is φ = 12010130112.

The previous prime is 12010130059. The next prime is 12010130117. The reversal of 12010130113 is 31103101021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11965734544 + 44395569 = 109388^2 + 6663^2 .

It is a cyclic number.

It is not a de Polignac number, because 12010130113 - 2²⁹ = 11473259201 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12010130093 and 12010130102.

It is not a weakly prime, because it can be changed into another prime (12010130117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005065056 + 6005065057.

It is an arithmetic number, because the mean of its divisors is an integer number (6005065057).

Almost surely, 2^12010130113 is an apocalyptic number.

It is an amenable number.

12010130113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12010130113 is an equidigital number, since it uses as much as digits as its factorization.

12010130113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 12010130113 its reverse (31103101021), we get a palindrome (43113231134).

The spelling of 12010130113 in words is "twelve billion, ten million, one hundred thirty thousand, one hundred thirteen".