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12010307 is a prime number
BaseRepresentation
bin101101110100…
…001101000011
3211121012001012
4231310031003
511033312212
61105231135
7204041321
oct55641503
924535035
1012010307
116863581
1240324ab
1326468ba
141848d11
1510c3922
hexb74343

12010307 has 2 divisors, whose sum is σ = 12010308. Its totient is φ = 12010306.

The previous prime is 12010303. The next prime is 12010309. The reversal of 12010307 is 70301021.

12010307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12010307 - 22 = 12010303 is a prime.

Together with 12010309, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12010291 and 12010300.

It is not a weakly prime, because it can be changed into another prime (12010303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005153 + 6005154.

It is an arithmetic number, because the mean of its divisors is an integer number (6005154).

Almost surely, 212010307 is an apocalyptic number.

12010307 is a deficient number, since it is larger than the sum of its proper divisors (1).

12010307 is an equidigital number, since it uses as much as digits as its factorization.

12010307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 42, while the sum is 14.

The square root of 12010307 is about 3465.5889831312. The cubic root of 12010307 is about 229.0083773624.

Adding to 12010307 its reverse (70301021), we get a palindrome (82311328).

The spelling of 12010307 in words is "twelve million, ten thousand, three hundred seven".