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1201054448413 is a prime number
BaseRepresentation
bin10001011110100100011…
…011000111101100011101
311020211010112211122021101
4101132210123013230131
5124134224414322123
62315431245033101
7152526151236451
oct21364433075435
94224115748241
101201054448413
11423400a19866
12174932855791
1389349ba9c91
14421ba5aa661
1521397574aad
hex117a46c7b1d

1201054448413 has 2 divisors, whose sum is σ = 1201054448414. Its totient is φ = 1201054448412.

The previous prime is 1201054448389. The next prime is 1201054448471. The reversal of 1201054448413 is 3148444501021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1195309263204 + 5745185209 = 1093302^2 + 75797^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201054448413 - 25 = 1201054448381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201054448483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600527224206 + 600527224207.

It is an arithmetic number, because the mean of its divisors is an integer number (600527224207).

Almost surely, 21201054448413 is an apocalyptic number.

It is an amenable number.

1201054448413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201054448413 is an equidigital number, since it uses as much as digits as its factorization.

1201054448413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 61440, while the sum is 37.

Adding to 1201054448413 its reverse (3148444501021), we get a palindrome (4349498949434).

The spelling of 1201054448413 in words is "one trillion, two hundred one billion, fifty-four million, four hundred forty-eight thousand, four hundred thirteen".