1201100000113 has 8 divisors (see below), whose sum is σ = 1293503757056. Its totient is φ = 1108697878800.

The previous prime is 1201100000033. The next prime is 1201100000119. The reversal of 1201100000113 is 3110000011021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1201100000113 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1201100000113.

It is not an unprimeable number, because it can be changed into a prime (1201100000119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1418878 + ... + 2101288.

It is an arithmetic number, because the mean of its divisors is an integer number (161687969632).

Almost surely, 2^{1201100000113} is an apocalyptic number.

1201100000113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1201100000113 is a deficient number, since it is larger than the sum of its proper divisors (92403756943).

1201100000113 is a wasteful number, since it uses less digits than its factorization.

1201100000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 817815.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 1201100000113 its reverse (3110000011021), we get a palindrome (4311100011134).

The spelling of 1201100000113 in words is "one trillion, two hundred one billion, one hundred million, one hundred thirteen", and thus it is an aban number.