12011001020993 has 8 divisors (see below), whose sum is σ = 12934951662528. Its totient is φ = 11087054306064.

The previous prime is 12011001020927. The next prime is 12011001020999. The reversal of 12011001020993 is 39902010011021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12011001020993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12011001020999) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9580580 + ... + 10761482.

It is an arithmetic number, because the mean of its divisors is an integer number (1616868957816).

Almost surely, 2^{12011001020993} is an apocalyptic number.

12011001020993 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12011001020993 is a deficient number, since it is larger than the sum of its proper divisors (923950641535).

12011001020993 is a wasteful number, since it uses less digits than its factorization.

12011001020993 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1963303.

The product of its (nonzero) digits is 972, while the sum is 29.

The spelling of 12011001020993 in words is "twelve trillion, eleven billion, one million, twenty thousand, nine hundred ninety-three".