12011020000033 has 48 divisors (see below), whose sum is σ = 12790213128000. Its totient is φ = 11276947059840.

The previous prime is 12011019999991. The next prime is 12011020000037. The reversal of 12011020000033 is 33000002011021.

It is a de Polignac number, because none of the positive numbers 2^k-12011020000033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12011019999968 and 12011020000022.

It is not an unprimeable number, because it can be changed into a prime (12011020000037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2761786743 + ... + 2761791091.

It is an arithmetic number, because the mean of its divisors is an integer number (266462773500).

Almost surely, 2^{12011020000033} is an apocalyptic number.

It is an amenable number.

12011020000033 is a deficient number, since it is larger than the sum of its proper divisors (779193127967).

12011020000033 is a wasteful number, since it uses less digits than its factorization.

12011020000033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4942 (or 4919 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 12011020000033 its reverse (33000002011021), we get a palindrome (45011022011054).

The spelling of 12011020000033 in words is "twelve trillion, eleven billion, twenty million, thirty-three", and thus it is an aban number and an uban number.