120110311313 has 2 divisors, whose sum is σ = 120110311314. Its totient is φ = 120110311312.

The previous prime is 120110311291. The next prime is 120110311319. The reversal of 120110311313 is 313113011021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 64512444049 + 55597867264 = 253993^2 + 235792^2 .

It is a cyclic number.

It is not a de Polignac number, because 120110311313 - 2²² = 120106117009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120110311291 and 120110311300.

It is not a weakly prime, because it can be changed into another prime (120110311319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60055155656 + 60055155657.

It is an arithmetic number, because the mean of its divisors is an integer number (60055155657).

Almost surely, 2^120110311313 is an apocalyptic number.

It is an amenable number.

120110311313 is a deficient number, since it is larger than the sum of its proper divisors (1).

120110311313 is an equidigital number, since it uses as much as digits as its factorization.

120110311313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 120110311313 its reverse (313113011021), we get a palindrome (433223322334).

The spelling of 120110311313 in words is "one hundred twenty billion, one hundred ten million, three hundred eleven thousand, three hundred thirteen".