Base | Representation |
---|---|
bin | 1010111011001000110001… |
… | …1110010110001010110111 |
3 | 1120112020201012001221220102 |
4 | 2232302030132112022313 |
5 | 3033242200320344413 |
6 | 41313452203024315 |
7 | 2346525614510153 |
oct | 256621436261267 |
9 | 46466635057812 |
10 | 12011085324983 |
11 | 39109665a0608 |
12 | 141b9b420b09b |
13 | 6918431c0294 |
14 | 2d74a7d40063 |
15 | 15c681216458 |
hex | aec8c7962b7 |
12011085324983 has 2 divisors, whose sum is σ = 12011085324984. Its totient is φ = 12011085324982.
The previous prime is 12011085324961. The next prime is 12011085324991. The reversal of 12011085324983 is 38942358011021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12011085324983 - 26 = 12011085324919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12011085324583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005542662491 + 6005542662492.
It is an arithmetic number, because the mean of its divisors is an integer number (6005542662492).
Almost surely, 212011085324983 is an apocalyptic number.
12011085324983 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011085324983 is an equidigital number, since it uses as much as digits as its factorization.
12011085324983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 414720, while the sum is 47.
The spelling of 12011085324983 in words is "twelve trillion, eleven billion, eighty-five million, three hundred twenty-four thousand, nine hundred eighty-three".
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