Base | Representation |
---|---|
bin | 1010111011001000110101… |
… | …0111001011001011000111 |
3 | 1120112020202020002210222101 |
4 | 2232302031113023023013 |
5 | 3033242213124102101 |
6 | 41313453454212531 |
7 | 2346526155234142 |
oct | 256621527131307 |
9 | 46466666083871 |
10 | 12011100222151 |
11 | 3910973a46018 |
12 | 141b9b91b4147 |
13 | 691846307b84 |
14 | 2d74a9cdb059 |
15 | 15c6826aa401 |
hex | aec8d5cb2c7 |
12011100222151 has 2 divisors, whose sum is σ = 12011100222152. Its totient is φ = 12011100222150.
The previous prime is 12011100222131. The next prime is 12011100222203. The reversal of 12011100222151 is 15122200111021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12011100222151 - 217 = 12011100091079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12011100222131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005550111075 + 6005550111076.
It is an arithmetic number, because the mean of its divisors is an integer number (6005550111076).
Almost surely, 212011100222151 is an apocalyptic number.
12011100222151 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011100222151 is an equidigital number, since it uses as much as digits as its factorization.
12011100222151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 12011100222151 its reverse (15122200111021), we get a palindrome (27133300333172).
The spelling of 12011100222151 in words is "twelve trillion, eleven billion, one hundred million, two hundred twenty-two thousand, one hundred fifty-one".
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