Base | Representation |
---|---|
bin | 10001011110100111101… |
… | …111110011101100000111 |
3 | 11020211021102202021101101 |
4 | 101132213233303230013 |
5 | 124134333203000033 |
6 | 2315441000040531 |
7 | 152530426162624 |
oct | 21364757635407 |
9 | 4224242667341 |
10 | 1201110203143 |
11 | 42342a440154 |
12 | 174949463147 |
13 | 893585cb846 |
14 | 421c3b6134b |
15 | 2139c3d997d |
hex | 117a7bf3b07 |
1201110203143 has 2 divisors, whose sum is σ = 1201110203144. Its totient is φ = 1201110203142.
The previous prime is 1201110203099. The next prime is 1201110203197. The reversal of 1201110203143 is 3413020111021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1201110203143 - 213 = 1201110194951 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1201110203143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201110203543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600555101571 + 600555101572.
It is an arithmetic number, because the mean of its divisors is an integer number (600555101572).
Almost surely, 21201110203143 is an apocalyptic number.
1201110203143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201110203143 is an equidigital number, since it uses as much as digits as its factorization.
1201110203143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1201110203143 its reverse (3413020111021), we get a palindrome (4614130314164).
The spelling of 1201110203143 in words is "one trillion, two hundred one billion, one hundred ten million, two hundred three thousand, one hundred forty-three".
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