1201112220031 has 2 divisors, whose sum is σ = 1201112220032. Its totient is φ = 1201112220030.

The previous prime is 1201112219999. The next prime is 1201112220137. The reversal of 1201112220031 is 1300222111021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1201112220031 - 2⁵ = 1201112219999 is a prime.

It is a super-2 number, since 2×1201112220031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1201112219987 and 1201112220014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201112221031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600556110015 + 600556110016.

It is an arithmetic number, because the mean of its divisors is an integer number (600556110016).

Almost surely, 2^{1201112220031} is an apocalyptic number.

1201112220031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201112220031 is an equidigital number, since it uses as much as digits as its factorization.

1201112220031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 1201112220031 its reverse (1300222111021), we get a palindrome (2501334331052).

The spelling of 1201112220031 in words is "one trillion, two hundred one billion, one hundred twelve million, two hundred twenty thousand, thirty-one".