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12011131142 = 217379547799
BaseRepresentation
bin10110010111110101…
…10101000100000110
31011000002001200101222
423023322311010012
5144044322144032
65303504120342
7603434634023
oct131372650406
934002050358
1012011131142
115103a7466a
1223b26060b2
1311955611ba
1481d2b854a
154a471da12
hex2cbeb5106

12011131142 has 16 divisors (see below), whose sum is σ = 19592085600. Its totient is φ = 5499531648.

The previous prime is 12011131141. The next prime is 12011131151. The reversal of 12011131142 is 24113111021.

12011131142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a self number, because there is not a number n which added to its sum of digits gives 12011131142.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12011131141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4772642 + ... + 4775157.

It is an arithmetic number, because the mean of its divisors is an integer number (1224505350).

Almost surely, 212011131142 is an apocalyptic number.

12011131142 is a deficient number, since it is larger than the sum of its proper divisors (7580954458).

12011131142 is a wasteful number, since it uses less digits than its factorization.

12011131142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9547855.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 12011131142 its reverse (24113111021), we get a palindrome (36124242163).

The spelling of 12011131142 in words is "twelve billion, eleven million, one hundred thirty-one thousand, one hundred forty-two".

Divisors: 1 2 17 34 37 74 629 1258 9547799 19095598 162312583 324625166 353268563 706537126 6005565571 12011131142