Base | Representation |
---|---|
bin | 1010111011001000111101… |
… | …0001001100111110111100 |
3 | 1120112020211110022000121110 |
4 | 2232302033101030332330 |
5 | 3033242244321224012 |
6 | 41313501000002020 |
7 | 2346530024155365 |
oct | 256621721147674 |
9 | 46466743260543 |
10 | 12011132211132 |
11 | 391099000489a |
12 | 141ba07a60310 |
13 | 69184cb28272 |
14 | 2d74b0266b6c |
15 | 15c6853c873c |
hex | aec8f44cfbc |
12011132211132 has 24 divisors (see below), whose sum is σ = 28026126231376. Its totient is φ = 4003689155328.
The previous prime is 12011132211119. The next prime is 12011132211227. The reversal of 12011132211132 is 23111223111021.
It is a junction number, because it is equal to n+sod(n) for n = 12011132211099 and 12011132211108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 293053 + ... + 4910004.
Almost surely, 212011132211132 is an apocalyptic number.
12011132211132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
12011132211132 is an abundant number, since it is smaller than the sum of its proper divisors (16014994020244).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12011132211132 is a wasteful number, since it uses less digits than its factorization.
12011132211132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5395437 (or 5395435 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 12011132211132 its reverse (23111223111021), we get a palindrome (35122355322153).
The spelling of 12011132211132 in words is "twelve trillion, eleven billion, one hundred thirty-two million, two hundred eleven thousand, one hundred thirty-two".
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