Base | Representation |
---|---|
bin | 100011110010111… |
… | …1000110001011111 |
3 | 10002201002220221101 |
4 | 1013211320301133 |
5 | 4424441123312 |
6 | 315104013531 |
7 | 41523205456 |
oct | 10745706137 |
9 | 3081086841 |
10 | 1201114207 |
11 | 566aa7977 |
12 | 2963012a7 |
13 | 161ac4687 |
14 | b573db9d |
15 | 706aaa57 |
hex | 47978c5f |
1201114207 has 2 divisors, whose sum is σ = 1201114208. Its totient is φ = 1201114206.
The previous prime is 1201114163. The next prime is 1201114231. The reversal of 1201114207 is 7024111021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1201114207 - 215 = 1201081439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201114247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600557103 + 600557104.
It is an arithmetic number, because the mean of its divisors is an integer number (600557104).
Almost surely, 21201114207 is an apocalyptic number.
1201114207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201114207 is an equidigital number, since it uses as much as digits as its factorization.
1201114207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 19.
The square root of 1201114207 is about 34657.0946127918. The cubic root of 1201114207 is about 1062.9873623349.
Adding to 1201114207 its reverse (7024111021), we get a palindrome (8225225228).
The spelling of 1201114207 in words is "one billion, two hundred one million, one hundred fourteen thousand, two hundred seven".
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