Base | Representation |
---|---|
bin | 11011010011110111000001… |
… | …110011110010011010001111 |
3 | 120202021121002122010202202001 |
4 | 123103313001303302122033 |
5 | 111220403400033324101 |
6 | 1103242410243013131 |
7 | 34204543425443266 |
oct | 3323670163623217 |
9 | 522247078122661 |
10 | 120112012011151 |
11 | 352a9244515056 |
12 | 1157a61996a1a7 |
13 | 520368b718004 |
14 | 21936495575dd |
15 | dd45c81d4901 |
hex | 6d3dc1cf268f |
120112012011151 has 2 divisors, whose sum is σ = 120112012011152. Its totient is φ = 120112012011150.
The previous prime is 120112012010987. The next prime is 120112012011161. The reversal of 120112012011151 is 151110210211021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120112012011151 - 215 = 120112011978383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120112012011161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60056006005575 + 60056006005576.
It is an arithmetic number, because the mean of its divisors is an integer number (60056006005576).
Almost surely, 2120112012011151 is an apocalyptic number.
120112012011151 is a deficient number, since it is larger than the sum of its proper divisors (1).
120112012011151 is an equidigital number, since it uses as much as digits as its factorization.
120112012011151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40, while the sum is 19.
Adding to 120112012011151 its reverse (151110210211021), we get a palindrome (271222222222172).
The spelling of 120112012011151 in words is "one hundred twenty trillion, one hundred twelve billion, twelve million, eleven thousand, one hundred fifty-one".
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