Base | Representation |
---|---|
bin | 1010111011001001001101… |
… | …1011011011100100101001 |
3 | 1120112021000022121201120112 |
4 | 2232302103123123210221 |
5 | 3033242420203014233 |
6 | 41313511531504105 |
7 | 2346531532316063 |
oct | 256622333334451 |
9 | 46467008551515 |
10 | 12011202001193 |
11 | 3910a1644212a |
12 | 141ba272b8035 |
13 | 691861422365 |
14 | 2d74b9632733 |
15 | 15c68b5b2048 |
hex | aec936db929 |
12011202001193 has 2 divisors, whose sum is σ = 12011202001194. Its totient is φ = 12011202001192.
The previous prime is 12011202001159. The next prime is 12011202001207. The reversal of 12011202001193 is 39110020211021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6980655420649 + 5030546580544 = 2642093^2 + 2242888^2 .
It is an emirp because it is prime and its reverse (39110020211021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12011202001193 - 234 = 11994022132009 is a prime.
It is not a weakly prime, because it can be changed into another prime (12011202001133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005601000596 + 6005601000597.
It is an arithmetic number, because the mean of its divisors is an integer number (6005601000597).
Almost surely, 212011202001193 is an apocalyptic number.
It is an amenable number.
12011202001193 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011202001193 is an equidigital number, since it uses as much as digits as its factorization.
12011202001193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 23.
The spelling of 12011202001193 in words is "twelve trillion, eleven billion, two hundred two million, one thousand, one hundred ninety-three".
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