Base | Representation |
---|---|
bin | 10001011110101000011… |
… | …001011101011101001001 |
3 | 11020211022012022000101222 |
4 | 101132220121131131021 |
5 | 124134344001401441 |
6 | 2315442030051425 |
7 | 152530621040444 |
oct | 21365031353511 |
9 | 4224265260358 |
10 | 1201121122121 |
11 | 4234356187a8 |
12 | 174951049b75 |
13 | 8935a95278b |
14 | 421c53a465b |
15 | 2139d344d4b |
hex | 117a865d749 |
1201121122121 has 2 divisors, whose sum is σ = 1201121122122. Its totient is φ = 1201121122120.
The previous prime is 1201121122087. The next prime is 1201121122129. The reversal of 1201121122121 is 1212211211021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 848535745600 + 352585376521 = 921160^2 + 593789^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1201121122121 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1201121122121.
It is not a weakly prime, because it can be changed into another prime (1201121122129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600560561060 + 600560561061.
It is an arithmetic number, because the mean of its divisors is an integer number (600560561061).
Almost surely, 21201121122121 is an apocalyptic number.
It is an amenable number.
1201121122121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201121122121 is an equidigital number, since it uses as much as digits as its factorization.
1201121122121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32, while the sum is 17.
Adding to 1201121122121 its reverse (1212211211021), we get a palindrome (2413332333142).
The spelling of 1201121122121 in words is "one trillion, two hundred one billion, one hundred twenty-one million, one hundred twenty-two thousand, one hundred twenty-one".
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