Base | Representation |
---|---|
bin | 1010111011001001101000… |
… | …0011010100110000011010 |
3 | 1120112021022001201021010012 |
4 | 2232302122003110300122 |
5 | 3033243132124403310 |
6 | 41313530541321522 |
7 | 2346534351660314 |
oct | 256623203246032 |
9 | 46467261637105 |
10 | 12011313122330 |
11 | 3910a7313a085 |
12 | 141ba585662a2 |
13 | 69187b45ab02 |
14 | 2d74ca2ba7b4 |
15 | 15c696211c05 |
hex | aec9a0d4c1a |
12011313122330 has 32 divisors (see below), whose sum is σ = 22172435208000. Its totient is φ = 4682340375552.
The previous prime is 12011313122293. The next prime is 12011313122339. The reversal of 12011313122330 is 3322131311021.
It is a junction number, because it is equal to n+sod(n) for n = 12011313122296 and 12011313122305.
It is not an unprimeable number, because it can be changed into a prime (12011313122339) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30913040 + ... + 31299179.
It is an arithmetic number, because the mean of its divisors is an integer number (692888600250).
Almost surely, 212011313122330 is an apocalyptic number.
12011313122330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12011313122330 is a deficient number, since it is larger than the sum of its proper divisors (10161122085670).
12011313122330 is a wasteful number, since it uses less digits than its factorization.
12011313122330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62212718.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 12011313122330 its reverse (3322131311021), we get a palindrome (15333444433351).
The spelling of 12011313122330 in words is "twelve trillion, eleven billion, three hundred thirteen million, one hundred twenty-two thousand, three hundred thirty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •