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1201132202003 = 1545177738153
BaseRepresentation
bin10001011110101001000…
…011101110100000010011
311020211022222010221010222
4101132221003232200103
5124134404320431003
62315443103343255
7152531114155346
oct21365103564023
94224288127128
101201132202003
114234408a6228
121749548b1b2b
1389360031a16
14421c6a4a45d
152139e2d2c38
hex117a90ee813

1201132202003 has 4 divisors (see below), whose sum is σ = 1201209955608. Its totient is φ = 1201054448400.

The previous prime is 1201132201961. The next prime is 1201132202029. The reversal of 1201132202003 is 3002022311021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1201132202003 - 214 = 1201132185619 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1201132202203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38853626 + ... + 38884527.

It is an arithmetic number, because the mean of its divisors is an integer number (300302488902).

Almost surely, 21201132202003 is an apocalyptic number.

1201132202003 is a deficient number, since it is larger than the sum of its proper divisors (77753605).

1201132202003 is an equidigital number, since it uses as much as digits as its factorization.

1201132202003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 77753604.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1201132202003 its reverse (3002022311021), we get a palindrome (4203154513024).

The spelling of 1201132202003 in words is "one trillion, two hundred one billion, one hundred thirty-two million, two hundred two thousand, three".

Divisors: 1 15451 77738153 1201132202003