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12011330213132 = 22197116313106453
BaseRepresentation
bin1010111011001001101100…
…0100100001010100001100
31120112021100020212120021212
42232302123010201110030
53033243201013310012
641313532351513552
72346534650151605
oct256623304412414
946467306776255
1012011330213132
113910a81852708
12141ba622288b8
13691881b63003
142d74cc688dac
1515c69798ab22
hexaec9b12150c

12011330213132 has 24 divisors (see below), whose sum is σ = 21144694664016. Its totient is φ = 5970041311808.

The previous prime is 12011330213111. The next prime is 12011330213149. The reversal of 12011330213132 is 23131203311021.

It is a junction number, because it is equal to n+sod(n) for n = 12011330213098 and 12011330213107.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5636783 + ... + 7469670.

It is an arithmetic number, because the mean of its divisors is an integer number (881028944334).

Almost surely, 212011330213132 is an apocalyptic number.

It is an amenable number.

12011330213132 is a deficient number, since it is larger than the sum of its proper divisors (9133364450884).

12011330213132 is a wasteful number, since it uses less digits than its factorization.

12011330213132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13107817 (or 13107815 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 12011330213132 its reverse (23131203311021), we get a palindrome (35142533524153).

The spelling of 12011330213132 in words is "twelve trillion, eleven billion, three hundred thirty million, two hundred thirteen thousand, one hundred thirty-two".

Divisors: 1 2 4 197 394 788 1163 2326 4652 229111 458222 916444 13106453 26212906 52425812 2581971241 5163942482 10327884964 15242804839 30485609678 60971219356 3002832553283 6005665106566 12011330213132