12011332133301 has 4 divisors (see below), whose sum is σ = 16015109511072. Its totient is φ = 8007554755532.

The previous prime is 12011332133299. The next prime is 12011332133327. The reversal of 12011332133301 is 10333123311021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12011332133301 - 2¹ = 12011332133299 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12011332133351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2001888688881 + ... + 2001888688886.

It is an arithmetic number, because the mean of its divisors is an integer number (4003777377768).

Almost surely, 2^{12011332133301} is an apocalyptic number.

It is an amenable number.

12011332133301 is a deficient number, since it is larger than the sum of its proper divisors (4003777377771).

12011332133301 is an equidigital number, since it uses as much as digits as its factorization.

12011332133301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4003777377770.

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 12011332133301 its reverse (10333123311021), we get a palindrome (22344455444322).

The spelling of 12011332133301 in words is "twelve trillion, eleven billion, three hundred thirty-two million, one hundred thirty-three thousand, three hundred one".