Base | Representation |
---|---|
bin | 110111111011101010… |
… | …0010101101111110101 |
3 | 102111000220121000021101 |
4 | 1233313110111233311 |
5 | 3431443013440201 |
6 | 131102423250101 |
7 | 11451344143516 |
oct | 1576724255765 |
9 | 374026530241 |
10 | 120113421301 |
11 | 46a37993235 |
12 | 1b3418a9931 |
13 | b432849a73 |
14 | 5b5642ca0d |
15 | 31cee0bd01 |
hex | 1bf7515bf5 |
120113421301 has 2 divisors, whose sum is σ = 120113421302. Its totient is φ = 120113421300.
The previous prime is 120113421193. The next prime is 120113421343. The reversal of 120113421301 is 103124311021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 64846113201 + 55267308100 = 254649^2 + 235090^2 .
It is an emirp because it is prime and its reverse (103124311021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 120113421301 - 211 = 120113419253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120113421371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60056710650 + 60056710651.
It is an arithmetic number, because the mean of its divisors is an integer number (60056710651).
Almost surely, 2120113421301 is an apocalyptic number.
It is an amenable number.
120113421301 is a deficient number, since it is larger than the sum of its proper divisors (1).
120113421301 is an equidigital number, since it uses as much as digits as its factorization.
120113421301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 120113421301 its reverse (103124311021), we get a palindrome (223237732322).
The spelling of 120113421301 in words is "one hundred twenty billion, one hundred thirteen million, four hundred twenty-one thousand, three hundred one".
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