Base | Representation |
---|---|
bin | 1010111011001001101111… |
… | …0011001000011100011011 |
3 | 1120112021101002212100110112 |
4 | 2232302123303020130123 |
5 | 3033243212130311102 |
6 | 41313533505434535 |
7 | 2346535156052321 |
oct | 256623363103433 |
9 | 46467332770415 |
10 | 12011342432027 |
11 | 3910a88738974 |
12 | 141ba6633ba4b |
13 | 691884550823 |
14 | 2d74d0149d11 |
15 | 15c698aa1252 |
hex | aec9bcc871b |
12011342432027 has 2 divisors, whose sum is σ = 12011342432028. Its totient is φ = 12011342432026.
The previous prime is 12011342432009. The next prime is 12011342432053. The reversal of 12011342432027 is 72023424311021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12011342432027 - 28 = 12011342431771 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12011342431984 and 12011342432002.
It is not a weakly prime, because it can be changed into another prime (12011342432827) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005671216013 + 6005671216014.
It is an arithmetic number, because the mean of its divisors is an integer number (6005671216014).
Almost surely, 212011342432027 is an apocalyptic number.
12011342432027 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011342432027 is an equidigital number, since it uses as much as digits as its factorization.
12011342432027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 12011342432027 its reverse (72023424311021), we get a palindrome (84034766743048).
The spelling of 12011342432027 in words is "twelve trillion, eleven billion, three hundred forty-two million, four hundred thirty-two thousand, twenty-seven".
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