Base | Representation |
---|---|
bin | 1010111011001010010100… |
… | …1101110110111110110010 |
3 | 1120112021210010011122111122 |
4 | 2232302211031312332302 |
5 | 3033244023102331310 |
6 | 41314001312142242 |
7 | 2346542115045446 |
oct | 256624515667662 |
9 | 46467703148448 |
10 | 12011500433330 |
11 | 3911059945662 |
12 | 141baab237982 |
13 | 6918ab1c1618 |
14 | 2d7507118826 |
15 | 15c6a78b1555 |
hex | aeca5376fb2 |
12011500433330 has 8 divisors (see below), whose sum is σ = 21620700780012. Its totient is φ = 4804600173328.
The previous prime is 12011500433321. The next prime is 12011500433341. The reversal of 12011500433330 is 3333400511021.
It can be written as a sum of positive squares in 2 ways, for example, as 11337234460561 + 674265972769 = 3367081^2 + 821137^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×120115004333302 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 12011500433330.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 600575021657 + ... + 600575021676.
Almost surely, 212011500433330 is an apocalyptic number.
12011500433330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12011500433330 is a deficient number, since it is larger than the sum of its proper divisors (9609200346682).
12011500433330 is a wasteful number, since it uses less digits than its factorization.
12011500433330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1201150043340.
The product of its (nonzero) digits is 3240, while the sum is 26.
Adding to 12011500433330 its reverse (3333400511021), we get a palindrome (15344900944351).
The spelling of 12011500433330 in words is "twelve trillion, eleven billion, five hundred million, four hundred thirty-three thousand, three hundred thirty".
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