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120115155031 is a prime number
BaseRepresentation
bin110111111011101101…
…0111101000001010111
3102111001000212002111121
41233313122331001113
53431443434430111
6131102524344411
711451364654234
oct1576732750127
9374030762447
10120115155031
1146a38967873
121b3423a5107
13b433005c41
145b5676078b
1531d0150871
hex1bf76bd057

120115155031 has 2 divisors, whose sum is σ = 120115155032. Its totient is φ = 120115155030.

The previous prime is 120115155023. The next prime is 120115155157. The reversal of 120115155031 is 130551511021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 120115155031 - 23 = 120115155023 is a prime.

It is a super-2 number, since 2×1201151550312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 120115154987 and 120115155005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120115150031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60057577515 + 60057577516.

It is an arithmetic number, because the mean of its divisors is an integer number (60057577516).

Almost surely, 2120115155031 is an apocalyptic number.

120115155031 is a deficient number, since it is larger than the sum of its proper divisors (1).

120115155031 is an equidigital number, since it uses as much as digits as its factorization.

120115155031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 750, while the sum is 25.

Adding to 120115155031 its reverse (130551511021), we get a palindrome (250666666052).

The spelling of 120115155031 in words is "one hundred twenty billion, one hundred fifteen million, one hundred fifty-five thousand, thirty-one".