Base | Representation |
---|---|
bin | 110111111011101101… |
… | …0111101000001010111 |
3 | 102111001000212002111121 |
4 | 1233313122331001113 |
5 | 3431443434430111 |
6 | 131102524344411 |
7 | 11451364654234 |
oct | 1576732750127 |
9 | 374030762447 |
10 | 120115155031 |
11 | 46a38967873 |
12 | 1b3423a5107 |
13 | b433005c41 |
14 | 5b5676078b |
15 | 31d0150871 |
hex | 1bf76bd057 |
120115155031 has 2 divisors, whose sum is σ = 120115155032. Its totient is φ = 120115155030.
The previous prime is 120115155023. The next prime is 120115155157. The reversal of 120115155031 is 130551511021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120115155031 - 23 = 120115155023 is a prime.
It is a super-2 number, since 2×1201151550312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 120115154987 and 120115155005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120115150031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60057577515 + 60057577516.
It is an arithmetic number, because the mean of its divisors is an integer number (60057577516).
Almost surely, 2120115155031 is an apocalyptic number.
120115155031 is a deficient number, since it is larger than the sum of its proper divisors (1).
120115155031 is an equidigital number, since it uses as much as digits as its factorization.
120115155031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 750, while the sum is 25.
Adding to 120115155031 its reverse (130551511021), we get a palindrome (250666666052).
The spelling of 120115155031 in words is "one hundred twenty billion, one hundred fifteen million, one hundred fifty-five thousand, thirty-one".
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