120120000201401 has 2 divisors, whose sum is σ = 120120000201402. Its totient is φ = 120120000201400.

The previous prime is 120120000201389. The next prime is 120120000201419. The reversal of 120120000201401 is 104102000021021.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90659247895225 + 29460752306176 = 9521515^2 + 5427776^2 .

It is a cyclic number.

It is not a de Polignac number, because 120120000201401 - 2³⁰ = 120118926459577 is a prime.

It is a super-3 number, since 3×120120000201401³ (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (120120000201101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060000100700 + 60060000100701.

It is an arithmetic number, because the mean of its divisors is an integer number (60060000100701).

Almost surely, 2^{120120000201401} is an apocalyptic number.

It is an amenable number.

120120000201401 is a deficient number, since it is larger than the sum of its proper divisors (1).

120120000201401 is an equidigital number, since it uses as much as digits as its factorization.

120120000201401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 120120000201401 its reverse (104102000021021), we get a palindrome (224222000222422).

The spelling of 120120000201401 in words is "one hundred twenty trillion, one hundred twenty billion, two hundred one thousand, four hundred one".