Base | Representation |
---|---|
bin | 10001011110101101000… |
… | …110010111001111100111 |
3 | 11020211111200201112021211 |
4 | 101132231012113033213 |
5 | 124140024200031043 |
6 | 2315453524452251 |
7 | 152532566360140 |
oct | 21365506271747 |
9 | 4224450645254 |
10 | 1201200002023 |
11 | 4234760a43aa |
12 | 17497354a087 |
13 | 893710b0088 |
14 | 421d1a58ac7 |
15 | 213a5226a9d |
hex | 117ad1973e7 |
1201200002023 has 16 divisors (see below), whose sum is σ = 1391057660160. Its totient is φ = 1015937436096.
The previous prime is 1201200002017. The next prime is 1201200002063. The reversal of 1201200002023 is 3202000021021.
It is a cyclic number.
It is not a de Polignac number, because 1201200002023 - 233 = 1192610067431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1201200001994 and 1201200002012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1201200002063) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 807765 + ... + 1747822.
It is an arithmetic number, because the mean of its divisors is an integer number (86941103760).
Almost surely, 21201200002023 is an apocalyptic number.
1201200002023 is a deficient number, since it is larger than the sum of its proper divisors (189857658137).
1201200002023 is an equidigital number, since it uses as much as digits as its factorization.
1201200002023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2556486.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 1201200002023 its reverse (3202000021021), we get a palindrome (4403200023044).
The spelling of 1201200002023 in words is "one trillion, two hundred one billion, two hundred million, two thousand, twenty-three".
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