Base | Representation |
---|---|
bin | 11011010011111110011110… |
… | …000000001100110101001111 |
3 | 120202022100201102020121212002 |
4 | 123103332132000030311033 |
5 | 111221021230303014134 |
6 | 1103250211115302515 |
7 | 34205245415550161 |
oct | 3323763600146517 |
9 | 522270642217762 |
10 | 120120001219919 |
11 | 35301674191928 |
12 | 1158008944aa3b |
13 | 520436295038c |
14 | 2193ba6612931 |
15 | dd48e479c87e |
hex | 6d3f9e00cd4f |
120120001219919 has 2 divisors, whose sum is σ = 120120001219920. Its totient is φ = 120120001219918.
The previous prime is 120120001219913. The next prime is 120120001219927. The reversal of 120120001219919 is 919912100021021.
It is a weak prime.
It is an emirp because it is prime and its reverse (919912100021021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 120120001219919 - 216 = 120120001154383 is a prime.
It is a super-2 number, since 2×1201200012199192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120120001219913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060000609959 + 60060000609960.
It is an arithmetic number, because the mean of its divisors is an integer number (60060000609960).
Almost surely, 2120120001219919 is an apocalyptic number.
120120001219919 is a deficient number, since it is larger than the sum of its proper divisors (1).
120120001219919 is an equidigital number, since it uses as much as digits as its factorization.
120120001219919 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 38.
The spelling of 120120001219919 in words is "one hundred twenty trillion, one hundred twenty billion, one million, two hundred nineteen thousand, nine hundred nineteen".
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