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12012000213 = 34004000071
BaseRepresentation
bin10110010111111100…
…01001001111010101
31011000010200211112210
423023332021033111
5144100033001323
65303534504033
7603445213533
oct131376111725
934003624483
1012012000213
115104508604
1223b2965019
1311957a6945
1481d463153
154a4841293
hex2cbf893d5

12012000213 has 4 divisors (see below), whose sum is σ = 16016000288. Its totient is φ = 8008000140.

The previous prime is 12012000211. The next prime is 12012000227. The reversal of 12012000213 is 31200021021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12012000213 - 21 = 12012000211 is a prime.

It is a super-2 number, since 2×120120002132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12012000211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2002000033 + ... + 2002000038.

It is an arithmetic number, because the mean of its divisors is an integer number (4004000072).

Almost surely, 212012000213 is an apocalyptic number.

It is an amenable number.

12012000213 is a deficient number, since it is larger than the sum of its proper divisors (4004000075).

12012000213 is an equidigital number, since it uses as much as digits as its factorization.

12012000213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4004000074.

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 12012000213 its reverse (31200021021), we get a palindrome (43212021234).

The spelling of 12012000213 in words is "twelve billion, twelve million, two hundred thirteen", and thus it is an aban number.

Divisors: 1 3 4004000071 12012000213