Base | Representation |
---|---|
bin | 1010111011001100001110… |
… | …1101110010100000010011 |
3 | 1120112100002210000000202212 |
4 | 2232303003231302200103 |
5 | 3033301100100320313 |
6 | 41314124151302335 |
7 | 2346560600235533 |
oct | 256630355624023 |
9 | 46470083000685 |
10 | 12012012120083 |
11 | 39112a1764478 |
12 | 142001267a9ab |
13 | 691960208c51 |
14 | 2d75550734c3 |
15 | 15c6d77873a8 |
hex | aecc3b72813 |
12012012120083 has 2 divisors, whose sum is σ = 12012012120084. Its totient is φ = 12012012120082.
The previous prime is 12012012120077. The next prime is 12012012120127. The reversal of 12012012120083 is 38002121021021.
12012012120083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12012012120083 - 28 = 12012012119827 is a prime.
It is not a weakly prime, because it can be changed into another prime (12012012120013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006006060041 + 6006006060042.
It is an arithmetic number, because the mean of its divisors is an integer number (6006006060042).
Almost surely, 212012012120083 is an apocalyptic number.
12012012120083 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012012120083 is an equidigital number, since it uses as much as digits as its factorization.
12012012120083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
The spelling of 12012012120083 in words is "twelve trillion, twelve billion, twelve million, one hundred twenty thousand, eighty-three".
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