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12012024113 is a prime number
BaseRepresentation
bin10110010111111100…
…01111000100110001
31011000010202001022222
423023332033010301
5144100034232423
65303535210425
7603445343315
oct131376170461
934003661288
1012012024113
115104524561
1223b2976a15
1311957b479b
1481d46bb45
154a48483c8
hex2cbf8f131

12012024113 has 2 divisors, whose sum is σ = 12012024114. Its totient is φ = 12012024112.

The previous prime is 12012024053. The next prime is 12012024121. The reversal of 12012024113 is 31142021021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11696855104 + 315169009 = 108152^2 + 17753^2 .

It is a cyclic number.

It is not a de Polignac number, because 12012024113 - 214 = 12012007729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12012024091 and 12012024100.

It is not a weakly prime, because it can be changed into another prime (12012024173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006012056 + 6006012057.

It is an arithmetic number, because the mean of its divisors is an integer number (6006012057).

Almost surely, 212012024113 is an apocalyptic number.

It is an amenable number.

12012024113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012024113 is an equidigital number, since it uses as much as digits as its factorization.

12012024113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 12012024113 its reverse (31142021021), we get a palindrome (43154045134).

The spelling of 12012024113 in words is "twelve billion, twelve million, twenty-four thousand, one hundred thirteen".