Base | Representation |
---|---|
bin | 11011010011111110110000… |
… | …100011000000001110111111 |
3 | 120202022101112002122211002221 |
4 | 123103332300203000032333 |
5 | 111221022344424130442 |
6 | 1103250302031430211 |
7 | 34205256214144132 |
oct | 3323766043001677 |
9 | 522271462584087 |
10 | 120120312333247 |
11 | 35301813866986 |
12 | 11580155685367 |
13 | 52043b223c6c5 |
14 | 2193bd5a7a219 |
15 | dd4911c54467 |
hex | 6d3fb08c03bf |
120120312333247 has 2 divisors, whose sum is σ = 120120312333248. Its totient is φ = 120120312333246.
The previous prime is 120120312333167. The next prime is 120120312333319. The reversal of 120120312333247 is 742333213021021.
It is a strong prime.
It is an emirp because it is prime and its reverse (742333213021021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 120120312333247 - 227 = 120120178115519 is a prime.
It is a super-2 number, since 2×1201203123332472 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120120312033247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060156166623 + 60060156166624.
It is an arithmetic number, because the mean of its divisors is an integer number (60060156166624).
Almost surely, 2120120312333247 is an apocalyptic number.
120120312333247 is a deficient number, since it is larger than the sum of its proper divisors (1).
120120312333247 is an equidigital number, since it uses as much as digits as its factorization.
120120312333247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36288, while the sum is 34.
Adding to 120120312333247 its reverse (742333213021021), we get a palindrome (862453525354268).
The spelling of 120120312333247 in words is "one hundred twenty trillion, one hundred twenty billion, three hundred twelve million, three hundred thirty-three thousand, two hundred forty-seven".
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