1201203434107 has 2 divisors, whose sum is σ = 1201203434108. Its totient is φ = 1201203434106.

The previous prime is 1201203434071. The next prime is 1201203434143. The reversal of 1201203434107 is 7014343021021.

Together with previous prime (1201203434071) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (1201203434071) and next prime (1201203434143).

It is a cyclic number.

It is not a de Polignac number, because 1201203434107 - 2³¹ = 1199055950459 is a prime.

It is a super-2 number, since 2×1201203434107² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1201203434147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600601717053 + 600601717054.

It is an arithmetic number, because the mean of its divisors is an integer number (600601717054).

Almost surely, 2^{1201203434107} is an apocalyptic number.

1201203434107 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201203434107 is an equidigital number, since it uses as much as digits as its factorization.

1201203434107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 28.

Adding to 1201203434107 its reverse (7014343021021), we get a palindrome (8215546455128).

The spelling of 1201203434107 in words is "one trillion, two hundred one billion, two hundred three million, four hundred thirty-four thousand, one hundred seven".