Base | Representation |
---|---|
bin | 11011010011111111011001… |
… | …100110100001010111000111 |
3 | 120202022110022002201212120201 |
4 | 123103333121212201113013 |
5 | 111221030302241334343 |
6 | 1103250454234511331 |
7 | 34205312246560264 |
oct | 3323773146412707 |
9 | 522273262655521 |
10 | 120121001121223 |
11 | 35302037648543 |
12 | 11580308295547 |
13 | 5204491b5465b |
14 | 2193c5d33626b |
15 | dd495245e94d |
hex | 6d3fd99a15c7 |
120121001121223 has 2 divisors, whose sum is σ = 120121001121224. Its totient is φ = 120121001121222.
The previous prime is 120121001121131. The next prime is 120121001121227. The reversal of 120121001121223 is 322121100121021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120121001121223 - 233 = 120112411186631 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 120121001121223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120121001121227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060500560611 + 60060500560612.
It is an arithmetic number, because the mean of its divisors is an integer number (60060500560612).
Almost surely, 2120121001121223 is an apocalyptic number.
120121001121223 is a deficient number, since it is larger than the sum of its proper divisors (1).
120121001121223 is an equidigital number, since it uses as much as digits as its factorization.
120121001121223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 120121001121223 its reverse (322121100121021), we get a palindrome (442242101242244).
The spelling of 120121001121223 in words is "one hundred twenty trillion, one hundred twenty-one billion, one million, one hundred twenty-one thousand, two hundred twenty-three".
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