Base | Representation |
---|---|
bin | 1010111011001100100011… |
… | …1101011100111100000011 |
3 | 1120112100022220120111011121 |
4 | 2232303020331130330003 |
5 | 3033301240112042011 |
6 | 41314141013253111 |
7 | 2346563016166240 |
oct | 256631075347403 |
9 | 46470286514147 |
10 | 12012100112131 |
11 | 39113373a4179 |
12 | 1420038034197 |
13 | 691975506c52 |
14 | 2d7562a1a5c7 |
15 | 15c6e0368e71 |
hex | aecc8f5cf03 |
12012100112131 has 16 divisors (see below), whose sum is σ = 14539978414080. Its totient is φ = 9687548465280.
The previous prime is 12012100112119. The next prime is 12012100112317. The reversal of 12012100112131 is 13121100121021.
It is a happy number.
It is not a de Polignac number, because 12012100112131 - 211 = 12012100110083 is a prime.
It is a super-2 number, since 2×120121001121312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12012100113131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14625885 + ... + 15425326.
It is an arithmetic number, because the mean of its divisors is an integer number (908748650880).
Almost surely, 212012100112131 is an apocalyptic number.
12012100112131 is a deficient number, since it is larger than the sum of its proper divisors (2527878301949).
12012100112131 is a wasteful number, since it uses less digits than its factorization.
12012100112131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30054594.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 12012100112131 its reverse (13121100121021), we get a palindrome (25133200233152).
The spelling of 12012100112131 in words is "twelve trillion, twelve billion, one hundred million, one hundred twelve thousand, one hundred thirty-one".
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