Base | Representation |
---|---|
bin | 1010111011001100100100… |
… | …0101000010110101010001 |
3 | 1120112100100001022121020112 |
4 | 2232303021011002311101 |
5 | 3033301241114233403 |
6 | 41314141124051105 |
7 | 2346563042125523 |
oct | 256631105026521 |
9 | 46470301277215 |
10 | 12012102102353 |
11 | 3911338533491 |
12 | 1420038833a95 |
13 | 691975a52ab2 |
14 | 2d7562db7a13 |
15 | 15c6e060d9d8 |
hex | aecc9142d51 |
12012102102353 has 2 divisors, whose sum is σ = 12012102102354. Its totient is φ = 12012102102352.
The previous prime is 12012102102349. The next prime is 12012102102359. The reversal of 12012102102353 is 35320120121021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10402218211009 + 1609883891344 = 3225247^2 + 1268812^2 .
It is a cyclic number.
It is not a de Polignac number, because 12012102102353 - 22 = 12012102102349 is a prime.
It is not a weakly prime, because it can be changed into another prime (12012102102359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006051051176 + 6006051051177.
It is an arithmetic number, because the mean of its divisors is an integer number (6006051051177).
Almost surely, 212012102102353 is an apocalyptic number.
It is an amenable number.
12012102102353 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012102102353 is an equidigital number, since it uses as much as digits as its factorization.
12012102102353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 12012102102353 its reverse (35320120121021), we get a palindrome (47332222223374).
The spelling of 12012102102353 in words is "twelve trillion, twelve billion, one hundred two million, one hundred two thousand, three hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •