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1201210220113 is a prime number
BaseRepresentation
bin10001011110101101101…
…101010101111001010001
311020211112101221122212121
4101132231231111321101
5124140034304020423
62315454531454241
7152533052255401
oct21365555257121
94224471848777
101201210220113
11423480943402
12174976a57381
1389373249c97
14421d3158801
15213a609445d
hex117adb55e51

1201210220113 has 2 divisors, whose sum is σ = 1201210220114. Its totient is φ = 1201210220112.

The previous prime is 1201210220099. The next prime is 1201210220123. The reversal of 1201210220113 is 3110220121021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1156072243264 + 45137976849 = 1075208^2 + 212457^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201210220113 - 217 = 1201210089041 is a prime.

It is not a weakly prime, because it can be changed into another prime (1201210220123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600605110056 + 600605110057.

It is an arithmetic number, because the mean of its divisors is an integer number (600605110057).

Almost surely, 21201210220113 is an apocalyptic number.

It is an amenable number.

1201210220113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201210220113 is an equidigital number, since it uses as much as digits as its factorization.

1201210220113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 1201210220113 its reverse (3110220121021), we get a palindrome (4311430341134).

The spelling of 1201210220113 in words is "one trillion, two hundred one billion, two hundred ten million, two hundred twenty thousand, one hundred thirteen".