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12012103131253 is a prime number
BaseRepresentation
bin1010111011001100100100…
…1000111110000001110101
31120112100100010020212121221
42232303021020332001311
53033301241400200003
641314141202110341
72346563053642321
oct256631110760165
946470303225557
1012012103131253
113911339076515
12142003904b3b1
13691976023204
142d75631a4981
1515c6e07637bd
hexaecc923e075

12012103131253 has 2 divisors, whose sum is σ = 12012103131254. Its totient is φ = 12012103131252.

The previous prime is 12012103131247. The next prime is 12012103131311. The reversal of 12012103131253 is 35213130121021.

12012103131253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9436649479569 + 2575453651684 = 3071913^2 + 1604822^2 .

It is a cyclic number.

It is not a de Polignac number, because 12012103131253 - 241 = 9813079875701 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12012103131653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006051565626 + 6006051565627.

It is an arithmetic number, because the mean of its divisors is an integer number (6006051565627).

Almost surely, 212012103131253 is an apocalyptic number.

It is an amenable number.

12012103131253 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012103131253 is an equidigital number, since it uses as much as digits as its factorization.

12012103131253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 12012103131253 its reverse (35213130121021), we get a palindrome (47225233252274).

The spelling of 12012103131253 in words is "twelve trillion, twelve billion, one hundred three million, one hundred thirty-one thousand, two hundred fifty-three".