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12012104031 = 34004034677
BaseRepresentation
bin10110010111111101…
…00010100101011111
31011000010220002221220
423023332202211133
5144100044312111
65303541024423
7603446125314
oct131376424537
934003802856
1012012104031
115104579604
1223b29b5113
131195811c85
1481d48cd0b
154a4861e06
hex2cbfa295f

12012104031 has 4 divisors (see below), whose sum is σ = 16016138712. Its totient is φ = 8008069352.

The previous prime is 12012104017. The next prime is 12012104053. The reversal of 12012104031 is 13040121021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12012104031 - 210 = 12012103007 is a prime.

It is a super-2 number, since 2×120121040312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12012104031.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12012104011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2002017336 + ... + 2002017341.

It is an arithmetic number, because the mean of its divisors is an integer number (4004034678).

Almost surely, 212012104031 is an apocalyptic number.

12012104031 is a deficient number, since it is larger than the sum of its proper divisors (4004034681).

12012104031 is an equidigital number, since it uses as much as digits as its factorization.

12012104031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4004034680.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 12012104031 its reverse (13040121021), we get a palindrome (25052225052).

The spelling of 12012104031 in words is "twelve billion, twelve million, one hundred four thousand, thirty-one".

Divisors: 1 3 4004034677 12012104031