Base | Representation |
---|---|
bin | 11011010011111111011111… |
… | …100011111111011000001001 |
3 | 120202022110120001220101112101 |
4 | 123103333133203333120021 |
5 | 111221031003341333113 |
6 | 1103250512210113401 |
7 | 34205314602552025 |
oct | 3323773743773011 |
9 | 522273501811471 |
10 | 120121101121033 |
11 | 35302089039911 |
12 | 1158033587b861 |
13 | 52044a979803c |
14 | 2193c6c727385 |
15 | dd495b1142dd |
hex | 6d3fdf8ff609 |
120121101121033 has 2 divisors, whose sum is σ = 120121101121034. Its totient is φ = 120121101121032.
The previous prime is 120121101121009. The next prime is 120121101121069. The reversal of 120121101121033 is 330121101121021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 82031368351689 + 38089732769344 = 9057117^2 + 6171688^2 .
It is a cyclic number.
It is not a de Polignac number, because 120121101121033 - 217 = 120121100989961 is a prime.
It is a super-3 number, since 3×1201211011210333 (a number of 43 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 120121101121033.
It is not a weakly prime, because it can be changed into another prime (120121101121433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060550560516 + 60060550560517.
It is an arithmetic number, because the mean of its divisors is an integer number (60060550560517).
Almost surely, 2120121101121033 is an apocalyptic number.
It is an amenable number.
120121101121033 is a deficient number, since it is larger than the sum of its proper divisors (1).
120121101121033 is an equidigital number, since it uses as much as digits as its factorization.
120121101121033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 120121101121033 its reverse (330121101121021), we get a palindrome (450242202242054).
The spelling of 120121101121033 in words is "one hundred twenty trillion, one hundred twenty-one billion, one hundred one million, one hundred twenty-one thousand, thirty-three".
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