Base | Representation |
---|---|
bin | 1010111011001100100110… |
… | …0111000100011110110011 |
3 | 1120112100100200002202200221 |
4 | 2232303021213010132303 |
5 | 3033301300410201003 |
6 | 41314142043153511 |
7 | 2346563211005401 |
oct | 256631147043663 |
9 | 46470320082627 |
10 | 12012111022003 |
11 | 39113425759a4 |
12 | 142003b815897 |
13 | 6919778569b1 |
14 | 2d756425a471 |
15 | 15c6e12c17bd |
hex | aecc99c47b3 |
12012111022003 has 2 divisors, whose sum is σ = 12012111022004. Its totient is φ = 12012111022002.
The previous prime is 12012111021947. The next prime is 12012111022019. The reversal of 12012111022003 is 30022011121021.
It is an a-pointer prime, because the next prime (12012111022019) can be obtained adding 12012111022003 to its sum of digits (16).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12012111022003 is a prime.
It is a super-2 number, since 2×120121110220032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12012111022063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006055511001 + 6006055511002.
It is an arithmetic number, because the mean of its divisors is an integer number (6006055511002).
Almost surely, 212012111022003 is an apocalyptic number.
12012111022003 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012111022003 is an equidigital number, since it uses as much as digits as its factorization.
12012111022003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 12012111022003 its reverse (30022011121021), we get a palindrome (42034122143024).
The spelling of 12012111022003 in words is "twelve trillion, twelve billion, one hundred eleven million, twenty-two thousand, three".
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