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12012111022003 is a prime number
BaseRepresentation
bin1010111011001100100110…
…0111000100011110110011
31120112100100200002202200221
42232303021213010132303
53033301300410201003
641314142043153511
72346563211005401
oct256631147043663
946470320082627
1012012111022003
1139113425759a4
12142003b815897
136919778569b1
142d756425a471
1515c6e12c17bd
hexaecc99c47b3

12012111022003 has 2 divisors, whose sum is σ = 12012111022004. Its totient is φ = 12012111022002.

The previous prime is 12012111021947. The next prime is 12012111022019. The reversal of 12012111022003 is 30022011121021.

It is an a-pointer prime, because the next prime (12012111022019) can be obtained adding 12012111022003 to its sum of digits (16).

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12012111022003 is a prime.

It is a super-2 number, since 2×120121110220032 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12012111022063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006055511001 + 6006055511002.

It is an arithmetic number, because the mean of its divisors is an integer number (6006055511002).

Almost surely, 212012111022003 is an apocalyptic number.

12012111022003 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012111022003 is an equidigital number, since it uses as much as digits as its factorization.

12012111022003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 12012111022003 its reverse (30022011121021), we get a palindrome (42034122143024).

The spelling of 12012111022003 in words is "twelve trillion, twelve billion, one hundred eleven million, twenty-two thousand, three".