12012111103117 has 2 divisors, whose sum is σ = 12012111103118. Its totient is φ = 12012111103116.

The previous prime is 12012111103103. The next prime is 12012111103133. The reversal of 12012111103117 is 71130111121021.

12012111103117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11610333871236 + 401777231881 = 3407394^2 + 633859^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12012111103117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12012111103147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006055551558 + 6006055551559.

It is an arithmetic number, because the mean of its divisors is an integer number (6006055551559).

Almost surely, 2^{12012111103117} is an apocalyptic number.

It is an amenable number.

12012111103117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012111103117 is an equidigital number, since it uses as much as digits as its factorization.

12012111103117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 22.

Adding to 12012111103117 its reverse (71130111121021), we get a palindrome (83142222224138).

The spelling of 12012111103117 in words is "twelve trillion, twelve billion, one hundred eleven million, one hundred three thousand, one hundred seventeen".