Base | Representation |
---|---|
bin | 1010111011001100100110… |
… | …1111011001101001010111 |
3 | 1120112100100211012201101001 |
4 | 2232303021233121221113 |
5 | 3033301301440041342 |
6 | 41314142202044131 |
7 | 2346563235402316 |
oct | 256631157315127 |
9 | 46470324181331 |
10 | 12012113205847 |
11 | 3911343827727 |
12 | 14200404a9647 |
13 | 69197813ca01 |
14 | 2d756466827d |
15 | 15c6e15a38b7 |
hex | aecc9bd9a57 |
12012113205847 has 2 divisors, whose sum is σ = 12012113205848. Its totient is φ = 12012113205846.
The previous prime is 12012113205821. The next prime is 12012113205877. The reversal of 12012113205847 is 74850231121021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12012113205847 - 231 = 12009965722199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12012113205877) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006056602923 + 6006056602924.
It is an arithmetic number, because the mean of its divisors is an integer number (6006056602924).
Almost surely, 212012113205847 is an apocalyptic number.
12012113205847 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012113205847 is an equidigital number, since it uses as much as digits as its factorization.
12012113205847 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 37.
Adding to 12012113205847 its reverse (74850231121021), we get a palindrome (86862344326868).
The spelling of 12012113205847 in words is "twelve trillion, twelve billion, one hundred thirteen million, two hundred five thousand, eight hundred forty-seven".
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