Base | Representation |
---|---|
bin | 1010111011001100100110… |
… | …1111110111111101010011 |
3 | 1120112100100211110000200102 |
4 | 2232303021233313331103 |
5 | 3033301302003030003 |
6 | 41314142204443015 |
7 | 2346563236430303 |
oct | 256631157677523 |
9 | 46470324400612 |
10 | 12012113330003 |
11 | 3911343901a36 |
12 | 142004054946b |
13 | 691978184387 |
14 | 2d756469b603 |
15 | 15c6e15ca588 |
hex | aecc9bf7f53 |
12012113330003 has 4 divisors (see below), whose sum is σ = 12074352259368. Its totient is φ = 11949874400640.
The previous prime is 12012113329961. The next prime is 12012113330017. The reversal of 12012113330003 is 30003331121021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12012113330003 - 26 = 12012113329939 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12012113332003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31119464393 + ... + 31119464778.
It is an arithmetic number, because the mean of its divisors is an integer number (3018588064842).
Almost surely, 212012113330003 is an apocalyptic number.
12012113330003 is a deficient number, since it is larger than the sum of its proper divisors (62238929365).
12012113330003 is an equidigital number, since it uses as much as digits as its factorization.
12012113330003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62238929364.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 12012113330003 its reverse (30003331121021), we get a palindrome (42015444451024).
The spelling of 12012113330003 in words is "twelve trillion, twelve billion, one hundred thirteen million, three hundred thirty thousand, three".
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