Base | Representation |
---|---|
bin | 11011010011111111100110… |
… | …001011010101110110000011 |
3 | 120202022110211210201201000102 |
4 | 123103333212023111312003 |
5 | 111221031220244144341 |
6 | 1103250531212513015 |
7 | 34205320421061545 |
oct | 3323774613256603 |
9 | 522273753651012 |
10 | 120121212099971 |
11 | 35302135749a45 |
12 | 11580366a7b76b |
13 | 52044c6783b54 |
14 | 2193c7d375695 |
15 | dd4965c36c9b |
hex | 6d3fe62d5d83 |
120121212099971 has 2 divisors, whose sum is σ = 120121212099972. Its totient is φ = 120121212099970.
The previous prime is 120121212099947. The next prime is 120121212100027. The reversal of 120121212099971 is 179990212121021.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120121212099971 - 218 = 120121211837827 is a prime.
It is not a weakly prime, because it can be changed into another prime (120121212099901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60060606049985 + 60060606049986.
It is an arithmetic number, because the mean of its divisors is an integer number (60060606049986).
Almost surely, 2120121212099971 is an apocalyptic number.
120121212099971 is a deficient number, since it is larger than the sum of its proper divisors (1).
120121212099971 is an equidigital number, since it uses as much as digits as its factorization.
120121212099971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81648, while the sum is 47.
The spelling of 120121212099971 in words is "one hundred twenty trillion, one hundred twenty-one billion, two hundred twelve million, ninety-nine thousand, nine hundred seventy-one".
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